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Given the function \( f(x) = \frac{1}{x^2 4} \), determine the domain of \( f(x) \) and find the values of \( x \) for which \( f(x) = 0 \).
To determine the domain of the function \( f(x) = \frac{1}{x^2 4} \), we need to identify the values of \( x \) for which the function is defined、The function is undefined where the denominator is zero because division by zero is not allowed、Therefore, we need to solve the equation \( x^2 4 = 0 \).
\[
x^2 4 = 0
\]
This can be factored as:
\[
(x 2)(x + 2) = 0
\]
Setting each factor equal to zero gives us the solutions:
\[
x 2 = 0 \quad \text{or} \quad x + 2 = 0
\]
\[
x = 2 \quad \text{or} \quad x = -2
\]
Thus, the function \( f(x) \) is undefined at \( x = 2 \) and \( x = -2 \)、Therefore, the domain of \( f(x) \) is all real numbers except \( x = 2 \) and \( x = -2 \)、In interval notation, the domain is:
\[
(-\infty, -2) \cup (-2, 2) \cup (2, \infty)
\]
Next, we need to find the values of \( x \) for which \( f(x) = 0 \)、We set the function equal to zero and solve for \( x \):
\[
\frac{1}{x^2 4} = 0
\]
However, there is no value of \( x \) that can make the fraction equal to zero because the numerator is 1, which is a non-zero constant、Therefore, there are no values of \( x \) for which \( f(x) = 0 \).
The final answers are:
The domain of \( f(x) \) is \(\boxed{(-\infty, -2) \cup (-2, 2) \cup (2, \infty)}\).
There are no values of \( x \) for which \( f(x) = 0 \)、\(\boxed{\text{No solution}}\).